JK MATHS
11th Maths Solutions Chapter 2 Basic Algebra Ex 2.2
Question 1.
Solve for x.
(i) |3 – x| < 7
Solution:
– 7 < 3 – x < 7
– 7 – 3 < – x < 7 – 3
– 10 < – x < 4 10 > x > – 4
– 4 < x < 10
∴ The solution set is x ∈ (-4, 10)
(ii) |4x – 5| ≥ -2
Solution:
(iii)
Solution:
(iv) |x| – 10 < -3
Solution:
|x| < -3 + 10 (= 7)
|x| < 7 ⇒ -7 < x < 7
Question 2.
Solve 1|2x−1|<6 and express the solution using the interval notation.
Solution:
Solve -3|x| + 5 ≤ – 2 and graph the solution set in a number line.
Solution:
-3 |x| + 5 ≤ – 2
-3 |x| ≤ – 2 – 5
-3 |x| ≤ – 7
3 |x| ≥ 7
|x| ≥ 73
Question 4.
Solve 2|x + 1| – 6 ≤ 7 and graph the solution set in a number line.
Solution:
Question 5.
Question 6.
Solve |5x – 12| < -2
Solution:










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